Monday, December 17, 2007

factor this

x^4 - 11x^2 + 1

First prize is an Amazon gift certificate for one hundred dollars, decreasing in value by one dollar for each minute the problem remains unsolved. If it takes more than one hour forty minutes, you owe me money.

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30 Comments:

Anonymous Robert said...

I'm pretty sure the answer is

  ((x^2) - 10.90833...) ((x^2) - 0.091673...)

but if that's truly the answer then I also believe that you don't really think it's a fantastic factoring problem and that you posted it to fuck with us.

Total time: 17 minutes.

December 17, 2007 9:28 PM  
Anonymous Robert said...

That's correct within four decimal digits. The coefficients of the factors themselves are not rational.

December 17, 2007 9:31 PM  
Blogger Bernie said...

Robert, don't factor with decimals. Seriously.

December 17, 2007 10:03 PM  
Anonymous Robert said...

Why?

December 17, 2007 11:21 PM  
Anonymous Robert said...

  ((x^2) - (10 + (90,833/100,000))) ((x^2) - (91,673/1,000,000))

Are you happier now, Bernie?

December 18, 2007 7:34 AM  
Blogger John Levenstein said...

robert, a little less brain power, a bit more intuition.

December 18, 2007 8:17 AM  
Blogger frank b. said...

John, you've been foiled again (pun intended).

Did you ever notice that when people say "no pun intended", what they really mean is "pun intended, and I'm even pointing out the existence of the pun just in case you didn't catch it"

December 18, 2007 8:29 AM  
Anonymous Robert said...

(x - pi) (x + e)

That's what my intuition says, anyway.

December 18, 2007 8:34 AM  
Blogger John Levenstein said...

i'm giving a big fucking hint. i have to because i just gave it to bernie. you have to add and subtract the same thing to make it a difference of squares. once you can put it in the form a^2 - b^2, you can reduce it to (a+b)(a-b). but you have to add and subtract something that puts it in that form.

December 18, 2007 11:09 AM  
Blogger John Levenstein said...

i can't take you by the hand anymore than i already have. either you're nerds or you're not.

December 18, 2007 1:05 PM  
Anonymous Robert said...

> but you have to add and subtract something that puts it in that form.

Pi?

December 18, 2007 2:03 PM  
Blogger Robert said...

That was a joke! Just a joke! And just because I haven't answered your hint yet doesn't mean I don't intend to!

December 18, 2007 2:04 PM  
Anonymous Robert said...

I've got some of my nerdiest friends working on this too. We're all a bit baffled, but also intrigued because there are some oddities here.

December 18, 2007 5:59 PM  
Anonymous Robert said...

Oh - by "some" I mean "one". But he's very nerdy!

December 18, 2007 6:00 PM  
Anonymous Robert said...

John, you can add and subtract 25(x^2) to get

  x^4 + 25(x^2) - 36(x^2) + 1

which "simplifies" to

  ((x^2 + 5x)(x^2 - 5x)) - ((6x + 1)(6x - 1))

but that's not a real satisfying answer, and isn't any simpler, actually. So I assume you have something else in mind?

Whatever you do, please don't post the answer to this great great puzzle yet!

(more serious than you might think).

December 18, 2007 6:27 PM  
Blogger John Levenstein said...

i have something else in mind. i would never consider something "factored" that has a minus sign in the middle like that (i'll take a minus sign inside the parentheses, of course)

December 18, 2007 6:32 PM  
Anonymous Robert said...

John, how arbitrary is the "11" in the "11x^2"? Are there other integers that would yield similar solutions? Would there be similar solutions for ALL integers? An infinite subset? A finite subset? Or only the number 11?

December 18, 2007 8:10 PM  
Blogger John Levenstein said...

this is based on a problem in a math tournament i was in when we were in high school. but there is more than one version of the problem. they don't all involve the number 11. i don't have any reason to believe the high school math tournament question had the number 11. but for what i presented, it's crucial.

December 18, 2007 8:34 PM  
Blogger frank b. said...

x^4-(11x^2)+1+9-9

leads to

(x^2-10)(x^2-1)-9

which probably leads further, but I need to go shovel the sidewalk.

December 19, 2007 4:09 AM  
Blogger John Levenstein said...

the answer will be posted today. the key is adding and subtracting something that creates the difference of two squares.

December 19, 2007 7:35 AM  
Anonymous Robert said...

Please don't post the answer yet!

December 19, 2007 9:06 AM  
Anonymous Robert said...

One more day.

December 19, 2007 10:26 AM  
Anonymous Robert said...

I give up.

December 19, 2007 8:20 PM  
Blogger John Levenstein said...

x^4-11x^2+1
x^4-11x^2+9x^2+1-9x^2
x^4-2x^2+1-9x^2
(x^2-1)^2-(3x)^2

a^2-b^2=(a+b)(a-b)

so this equals...

(x^2+3x-1)(x^2-3x-1)

December 19, 2007 8:53 PM  
Blogger Robert said...

Did you solve the problem in the math tournament?

December 19, 2007 11:50 PM  
Blogger John Levenstein said...

i did not solve the question in the tournament.

December 20, 2007 7:07 AM  
Blogger Paul said...

Perhaps you would have gotten it if you were on performance enhancing drugs
http://chronicle.com/daily/2007/12/1052n.htm

December 20, 2007 9:10 AM  
Blogger John Levenstein said...

i think i would have gotten it if someone had told me i needed to add and subtract the same thing to make it the difference of squares. and then given me two days.

December 20, 2007 9:20 AM  
Blogger Bernie said...

Paul has a point. Someone needs to poke around all competitive venues to check for performance-enhancing drugs.

December 20, 2007 10:13 AM  
Blogger frank b. said...

You remembered the question from the tournament, which is remarkable in itself. I came across my high school yearbook recently ("sophomore" is spelled "sophmore" every single time) and learned that I was on the math team. I have no memories of this.

December 20, 2007 3:43 PM  

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